f(xy)=f(x)f(y)

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f(xy)=f(x)f(y)
f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)

f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)证明令x=x/y,y=y∵f(xy)

f(x+y)=f(x)+f(y)+2xy

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f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式

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f(xy)=f(x)+f(y)的单调性

f(xy)=f(x)+f(y)的单调性f(xy)=f(x)+f(y)的单调性f(xy)=f(x)+f(y)的单调性令x=y=0f(0)=f(0)+f(0)f(0)=0令y=-xf(x-x)=f(x)+f(-x)0=f(x)+f(-x)f(x

f(xy)=f(x)+f(y),证明f(1/x)=-f(x)

f(xy)=f(x)+f(y),证明f(1/x)=-f(x)f(xy)=f(x)+f(y),证明f(1/x)=-f(x)f(xy)=f(x)+f(y),证明f(1/x)=-f(x)证明:取x=1,y=1,则f(xy)=f(x)+f(y)即f

已知f(xy)=f(x)+f(y),求证f(x/y)=f(x)-f(y)

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f(x/Y)=f(x)-f(y) 求证明 f(xy)=f(x)+f(y)

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以知f(xy)=f(x)+f(y)求证f(x/y)=f(x)-f(y)

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f(xy)=f(x)+f(y),f(2)=1,f(3)=?

f(xy)=f(x)+f(y),f(2)=1,f(3)=?f(xy)=f(x)+f(y),f(2)=1,f(3)=?f(xy)=f(x)+f(y),f(2)=1,f(3)=?f(xy)=f(x)+f(y)令x=2,y=1代入得f(2)=f(

f(xy)=f(x)+f(y)且f(8)=3则f(2)=

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f(xy)=f(x)+f(y),f(8)=3,则f(根2)等于

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f(xy)=f(x)+f(y),f(8)=3,求f(√2),

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