x=y+z+2,x²=y²+z²+2yz+200 求 x+y+z=?
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![x=y+z+2,x²=y²+z²+2yz+200 求 x+y+z=?](/uploads/image/z/10144617-33-7.jpg?t=x%3Dy%2Bz%2B2%2Cx%26%23178%3B%3Dy%26%23178%3B%2Bz%26%23178%3B%2B2yz%2B200+%E6%B1%82+x%2By%2Bz%3D%3F)
x=y+z+2,x²=y²+z²+2yz+200 求 x+y+z=?
x=y+z+2,x²=y²+z²+2yz+200 求 x+y+z=?
x=y+z+2,x²=y²+z²+2yz+200 求 x+y+z=?
由x=y+z+2,x²=y²+z²+2yz+200
得x-2=y+z,x²=(y+z)²+200
所以x²=(x-2)²+200
x²=x²-4x+4+200
4x=4+200
x=51
所以y+z=51-2=49
所以x+y+z=100