u²+v²-x²-y=0 -u+v-xy+1=0 求∂u/∂x,∂v/∂x
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![u²+v²-x²-y=0 -u+v-xy+1=0 求∂u/∂x,∂v/∂x](/uploads/image/z/10184289-33-9.jpg?t=u%26%23178%3B%2Bv%26%23178%3B-x%26%23178%3B-y%3D0+-u%2Bv-xy%2B1%3D0+%E6%B1%82%26%238706%3Bu%2F%26%238706%3Bx%2C%26%238706%3Bv%2F%26%238706%3Bx)
u²+v²-x²-y=0 -u+v-xy+1=0 求∂u/∂x,∂v/∂x
u²+v²-x²-y=0 -u+v-xy+1=0 求∂u/∂x,∂v/∂x
u²+v²-x²-y=0 -u+v-xy+1=0 求∂u/∂x,∂v/∂x
x、y自变量,将式子对x偏导
u²+v²-x²-y=0 ,对x求导
2uu' + 2vv' - 2x = 0
uu' + vv' - x = 0(1)
-u+v-xy+1=0
-u'+v'-y=0(2)
联立(1)(2)
解u',v'