设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围
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![设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围](/uploads/image/z/10190055-39-5.jpg?t=%E8%AE%BEf%28x%29%3D%28x%2B1%2Fx%29%5E2+%2Cx%3E0.%281%29+%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%8F%8D%E5%87%BD%E6%95%B0f-1%28x%29%E6%8B%9C%E6%89%98%E5%90%84%E4%BD%8D%E4%BA%86+3Q%282%29%E8%8B%A5x%E2%89%A52%E6%97%B6%2C%E4%B8%8D%E7%AD%89%E5%BC%8F%28x-1%29f-1%28x%29%3Ea%28a-%E2%88%9Ax%29%E6%81%92%E6%88%90%E7%AB%8B%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围
设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q
(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围
设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围
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