(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004等于多少
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 11:21:41
![(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004等于多少](/uploads/image/z/1020653-53-3.jpg?t=%EF%BC%881%2F2%2B1%2F3%2B1%2F%2F4%2B%E2%80%A6%2B1%2F2005%EF%BC%89%281%2B1%2F2%2B1%2F3%2B1%2F4%2B%E2%80%A6%2B1%2F2004%29-%281%2B1%2F2%2B1%2F3%2B1%2F4%2B%E2%80%A6%2B1%2F2005%29%281%2F2%2B1%2F3%2B1%2F4%2B%E2%80%A6%2B1%2F2004%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91)
(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004等于多少
(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004
等于多少
(1/2+1/3+1//4+…+1/2005)(1+1/2+1/3+1/4+…+1/2004)-(1+1/2+1/3+1/4+…+1/2005)(1/2+1/3+1/4+…+1/2004等于多少
设1/2+1/3+1/4+…+1/2004=x
原式=(x+1/2005)(1+x)-(1+x+1/2005)x=x^2+x/2005+1/2005+x-(x+x^2+x/2005)=1/2005