设集合A={x/x2-ax+a2-19=0},B{x/x2-5x+6=0}.C={x/x2+2x-8=0},若空集真包含AnB,Anc=空集,求a的值
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![设集合A={x/x2-ax+a2-19=0},B{x/x2-5x+6=0}.C={x/x2+2x-8=0},若空集真包含AnB,Anc=空集,求a的值](/uploads/image/z/1030565-29-5.jpg?t=%E8%AE%BE%E9%9B%86%E5%90%88A%3D%EF%BD%9Bx%2Fx2-ax%2Ba2-19%3D0%7D%2CB%7Bx%2Fx2-5x%2B6%3D0%7D.C%3D%7Bx%2Fx2%2B2x-8%3D0%7D%2C%E8%8B%A5%E7%A9%BA%E9%9B%86%E7%9C%9F%E5%8C%85%E5%90%ABAnB%2CAnc%3D%E7%A9%BA%E9%9B%86%2C%E6%B1%82a%E7%9A%84%E5%80%BC)
设集合A={x/x2-ax+a2-19=0},B{x/x2-5x+6=0}.C={x/x2+2x-8=0},若空集真包含AnB,Anc=空集,求a的值
设集合A={x/x2-ax+a2-19=0},B{x/x2-5x+6=0}.C={x/x2+2x-8=0},若空集真包含AnB,Anc=空集,求a的值
设集合A={x/x2-ax+a2-19=0},B{x/x2-5x+6=0}.C={x/x2+2x-8=0},若空集真包含AnB,Anc=空集,求a的值
A={x|x2-ax+a2-19=0},
B={x|x2-5x+6=0}
= {x| (x-2)(x-3) =0 }
= {2,3}
C={x|x2+2x-8=0}
={ x| (x+4)(x-2)=0 }
= {-4,2}
if A∩B=ø
=> 2,3 不属于A
for x=2
4-2a+a2-19 ≠ 0
a2-2a-15≠ 0
(a-5)(a+3)≠ 0
a ≠ 5 or a ≠ -3
for x=3
9-3a+a2-19 ≠ 0
a2-3a-10 ≠ 0
(a-5)(a+2)≠ 0
a ≠ 5 and a ≠ -2
and A∩C=ø
=> -4,2 不属于 A
for x=-4
16+4a+a2-19 ≠ 0
a2+4a-3 ≠ 0
a ≠ -2+√7 or and a ≠ -2-√7
for x=2,we have a ≠ 5 or a ≠ -3
we have
(a ≠ 5 or a ≠ -3) and (a ≠ 5 and a ≠ -2) and (a ≠ -2+√7 or and a ≠ -2-√7)
ie a ≠ 5 and a ≠ -3 and a ≠ -2 and a ≠ -2+√7 and a ≠ -2-√7 #
8-8a+a8-89不等于1 a不等于8或-8 由上条件可得 a=-8 B=8、8B={x|x8-8x+8=1}={x:x=8,8} C={x|x8+8x-8=1}={x