设数列{an}为等比数列,数列{bn}满足bN=na1+(n-1)a2+…+2an-1+an,n属于正整数.已知b1=m,b2=3m/2,其中m
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![设数列{an}为等比数列,数列{bn}满足bN=na1+(n-1)a2+…+2an-1+an,n属于正整数.已知b1=m,b2=3m/2,其中m](/uploads/image/z/10342962-18-2.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E6%95%B0%E5%88%97%7Bbn%7D%E6%BB%A1%E8%B6%B3bN%3Dna1%2B%28n-1%29a2%2B%E2%80%A6%2B2an-1%2Ban%2Cn%E5%B1%9E%E4%BA%8E%E6%AD%A3%E6%95%B4%E6%95%B0.%E5%B7%B2%E7%9F%A5b1%3Dm%2Cb2%3D3m%2F2%2C%E5%85%B6%E4%B8%ADm)
设数列{an}为等比数列,数列{bn}满足bN=na1+(n-1)a2+…+2an-1+an,n属于正整数.已知b1=m,b2=3m/2,其中m
设数列{an}为等比数列,数列{bn}满足bN=na1+(n-1)a2+…+2an-1+an,n属于正整数.已知b1=m,b2=3m/2,其中m
设数列{an}为等比数列,数列{bn}满足bN=na1+(n-1)a2+…+2an-1+an,n属于正整数.已知b1=m,b2=3m/2,其中m
m不等于0,求数列an的首项和
令等比数列an=a1q^(n-1),
b1=a1=m,
b2=2a1+a2=(3/2)m,
联立争得a2=-(1/2)m,
则q=a2/a1=-1/2,
则an是一个以m为首项,-1/2为公比的等比数列!