1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/32.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-23.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4
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![1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/32.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-23.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4](/uploads/image/z/10477491-51-1.jpg?t=1.%28x%26sup2%3B-9%29%2F%28x%26sup2%3B%2B2x%26sup2%3B%2Bx%29%2A%283x%26sup3%3B%2B9x%26sup2%3B%29%2F%28x%26sup3%3B-3x%29%2C%E5%85%B6%E4%B8%ADx%3D-1%2F32.2x%2F%EF%BC%88x%26%23179%3B%2B2x%26%23178%3B%2Bx%EF%BC%89%E9%99%A4%E4%BB%A5%EF%BC%88x-1%EF%BC%89%2F%EF%BC%88x%26%23178%3B%2Bx%EF%BC%89%2C%E5%85%B6%E4%B8%ADx%3D-23.%284x%26%23178%3B-1%29%2F%EF%BC%882-4x%EF%BC%89%E9%99%A4%E4%BB%A5%EF%BC%884x%26%23178%3B%2B4x%2B1%EF%BC%89%2Fx%2C%E5%85%B6%E4%B8%ADx%3D-1%2F4)
1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/32.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-23.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4
1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/3
2.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-2
3.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4
1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/32.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-23.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4
2 =2x/x(x^2+2x+1) 乘以 x^2+x/x-1= 2x/x(x+1)^2乘以x(x+1)/x-1 = 2x/x^2-1 =-4/3
3 =(2x+1)(2x-1)/2(1-2x)乘以x/(2x+1)^2 =-x/2 =1/8
第一题 个人认为 不利于化简计算 是不是把题抄错了 ?如果要 直接带入肯定能算出来 但是很麻烦
1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/3
=(x-3)(x+3)/x(x+1)²*3x²(x+3)/x(x-3)
=3(x+3)²/(x+1)²
=(3×64/9)/(4/9)
=48
2.2x/(x...
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1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/3
=(x-3)(x+3)/x(x+1)²*3x²(x+3)/x(x-3)
=3(x+3)²/(x+1)²
=(3×64/9)/(4/9)
=48
2.2x/(x³+2x²+x)除以(x-1)/(x²+x),其中x=-2
=2/(x+1)²*x(x+1)/(x-1)
=2x/(x+1)(x-1)
=-4/(-2+1)(-2-1)
=-4/3
3.(4x²-1)/(2-4x)除以(4x²+4x+1)/x,其中x=-1/4
=(2x-1)(2x+1)/2(1-2x)*x/(2x+1)²
=-x/2(2x+1)
=(1/4)/[2×(2×(-1/4)+1)]
=1/4
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