A={2x^2-ax+b=0},B{x|bx^2+(a+2)x+5+b=0},且A交B={1/2},求A并B
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![A={2x^2-ax+b=0},B{x|bx^2+(a+2)x+5+b=0},且A交B={1/2},求A并B](/uploads/image/z/11335699-19-9.jpg?t=A%3D%EF%BD%9B2x%5E2-ax%2Bb%3D0%EF%BD%9D%2CB%EF%BD%9Bx%7Cbx%5E2%2B%28a%2B2%29x%2B5%2Bb%3D0%EF%BD%9D%2C%E4%B8%94A%E4%BA%A4B%3D%EF%BD%9B1%2F2%EF%BD%9D%2C%E6%B1%82A%E5%B9%B6B)
A={2x^2-ax+b=0},B{x|bx^2+(a+2)x+5+b=0},且A交B={1/2},求A并B
A={2x^2-ax+b=0},B{x|bx^2+(a+2)x+5+b=0},且A交B={1/2},求A并B
A={2x^2-ax+b=0},B{x|bx^2+(a+2)x+5+b=0},且A交B={1/2},求A并B
A交B={1/2}
所以1/2是A和B的方程的根
代入
1/2-a/2+b=0
b/2+a/2+1+5+b=0
b=-13/5,a=-21/5
解出方程即可
第一个是x=-13/5,x=1/2
第二个x=-35/26,x=1/2
{-13/5.1/2.-35/26}