int a[] = {0,1,2,3,4,5,6,7,8,9},*p = a,i; 其中0≤i≤9,A、a[p - a](这里不懂)B、*(&a[i]) (这个也不懂)
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![int a[] = {0,1,2,3,4,5,6,7,8,9},*p = a,i; 其中0≤i≤9,A、a[p - a](这里不懂)B、*(&a[i]) (这个也不懂)](/uploads/image/z/11479543-7-3.jpg?t=int+a%5B%5D+%3D+%7B0%2C1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%7D%2C%2Ap+%3D+a%2Ci%3B+%E5%85%B6%E4%B8%AD0%E2%89%A4i%E2%89%A49%2CA%E3%80%81a%5Bp+-+a%5D%EF%BC%88%E8%BF%99%E9%87%8C%E4%B8%8D%E6%87%82%EF%BC%89B%E3%80%81%2A%28%26a%5Bi%5D%29+%28%E8%BF%99%E4%B8%AA%E4%B9%9F%E4%B8%8D%E6%87%82%29)
int a[] = {0,1,2,3,4,5,6,7,8,9},*p = a,i; 其中0≤i≤9,A、a[p - a](这里不懂)B、*(&a[i]) (这个也不懂)
int a[] = {0,1,2,3,4,5,6,7,8,9},*p = a,i; 其中0≤i≤9,A、a[p - a](这里不懂)
B、*(&a[i]) (这个也不懂)
int a[] = {0,1,2,3,4,5,6,7,8,9},*p = a,i; 其中0≤i≤9,A、a[p - a](这里不懂)B、*(&a[i]) (这个也不懂)
int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
是定义了一个数组a,里面是初始化的数
*p = a,是用指针p指向数组a
a[p-a]这个里面p-a,因为p指向的是a的头,所以p=a(都是地址)
所以a[p-a]就相当于a[0]
*(&a[i]): a[i]是个数,就像a[0]=0,a[1]=1等
&是取地址符,就是取一个变量的地址,&a[0]就是取a[0]这个数的地址
而*是取数符,根据地址取出这个地址里的数
所以*(&a[i])实际上就是a[i],先取地址又根据地址取数而已