先化简再求值,x²-2x+1分之x²-1+x-2分之x²-2x÷x,其中x=根号5+1
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![先化简再求值,x²-2x+1分之x²-1+x-2分之x²-2x÷x,其中x=根号5+1](/uploads/image/z/11632251-3-1.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%2Cx%26%23178%3B-2x%2B1%E5%88%86%E4%B9%8Bx%26%23178%3B-1%2Bx-2%E5%88%86%E4%B9%8Bx%26%23178%3B-2x%C3%B7x%2C%E5%85%B6%E4%B8%ADx%3D%E6%A0%B9%E5%8F%B75%2B1)
先化简再求值,x²-2x+1分之x²-1+x-2分之x²-2x÷x,其中x=根号5+1
先化简再求值,x²-2x+1分之x²-1+x-2分之x²-2x÷x,其中x=根号5+1
先化简再求值,x²-2x+1分之x²-1+x-2分之x²-2x÷x,其中x=根号5+1
(x^2-1)/(x^2-2x+1)+(x^2-2x)/(x-2)÷x
=[(x+1)(x-1)]/(x-1)^2+x(x-2)/(x-2)X1/x
=(x+1)/(x-1)+1
=2x/(x-1)
因为x=根号5+1
所以原式=2(根号5+1)/(根号5+1-1)
=2/5倍(5+根号5)