(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
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![(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b](/uploads/image/z/1268016-24-6.jpg?t=%281%29%281%2Fa%2B1%2Fb%29%5E2%C3%B7%EF%BC%881%2Fa%5E2-1%2Fb%5E2%EF%BC%89+%282%29%28a%2Bb%2Fa-b%29%5E2%2A2a-2b%2F3a%2B3b+-a%5E2%2Fa%5E2-b%5E2%C3%B7a%2Fb)
(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
(1)(1/a+1/b)^2÷(1/a^2-1/b^2)
=(1)(1/a+1/b)^2÷【(1/a-1/b)*(1/a+1/b) 】
=(1/a+1/b)÷(1/a-1/b)
=(a+b)/(b-a)
(2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
=2(a+b)/[3(a-b)]-ab/(a^2-b^2)
=(2a^2+2b^2+ab)/【3(a^2-b^2)】
这题可能有错误,因为我看不懂你的题目,貌似题目有歧义,你少打括号了