①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
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①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
①原式=【(2x-3)+y】²=(2x-3)²+2(2x-3)y+y²=4x²-12x+9+4xy-6y+y²=4x²+4xy+y²-12x-6y+3
②原式=【(3x+2y)+4】×【(3x+2y)-4】=(3x+2y)²-4²=9x²+12xy+4y²-16