因式分解(1)4a²-16(2)4x²y+12xy+9y(3)m²(m+1)-(m+1)(4)a²-2a²b²+b的4次方
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![因式分解(1)4a²-16(2)4x²y+12xy+9y(3)m²(m+1)-(m+1)(4)a²-2a²b²+b的4次方](/uploads/image/z/1333810-10-0.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%281%294a%26%23178%3B-16%282%294x%26%23178%3By%2B12xy%2B9y%283%29m%26%23178%3B%28m%2B1%29-%28m%2B1%29%EF%BC%884%EF%BC%89a%26%23178%3B-2a%26%23178%3Bb%26%23178%3B%2Bb%E7%9A%844%E6%AC%A1%E6%96%B9)
因式分解(1)4a²-16(2)4x²y+12xy+9y(3)m²(m+1)-(m+1)(4)a²-2a²b²+b的4次方
因式分解(1)4a²-16(2)4x²y+12xy+9y(3)m²(m+1)-(m+1)
(4)a²-2a²b²+b的4次方
因式分解(1)4a²-16(2)4x²y+12xy+9y(3)m²(m+1)-(m+1)(4)a²-2a²b²+b的4次方
(1)4a^2-16=(2a+4)(2a-4)=4(a+2)(a-2)
(2)4z^2y+12xy+9y=y(2x+3)^2
(3)m^2(m+1)-(m+1)=(m+1)(m^2-1)=(m+1)^2(m-1)
(4)a^4-2a^2b^2+b^4=(a^2-b^2)^2=(a+b)^2(a-b)^2
1、4a²-16=(2a+4)(2a-4)
2、4x²y+12xy+9y=y(4x²+12x+9)=y(2x+3)²
3、m²(m+1)-(m+1)=(m+1)²(m-1)
4、a²-2a²b²+b⁴=a²-a²b²+b⁴-a²b²=a²(1+b)(1-b)-b²(a+b)(a-b)