计算9(x-1)²-(3x+3)(3x-1)
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计算9(x-1)²-(3x+3)(3x-1)
计算9(x-1)²-(3x+3)(3x-1)
计算9(x-1)²-(3x+3)(3x-1)
原式=9(x²-2x+1)-(9x²-3x+9x-3)
=9x²-18x+9-9x²+3x-9x+3
=-24x12
9(x-1)²-(3x+3)(3x-1)
=9x^2-18x+9-9x^2-9x+3x+3
=-24x+12
=-12(2x-1)
9(x-1)²-(3x+3)(3x-1)
=9(x²-2x+1)-(9x²+6x-3)
=9x²-18x+9-9x²-6x+3
=-24x+12
十世
原式=9(x²-2x+1)-(9x²+6x-3)
=9x²-18x+9-9x²-6x+3
=-24x+12
=12(1-2x)