x2+2y^2-2x+4y^2=-3 求(x+y)^2005
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![x2+2y^2-2x+4y^2=-3 求(x+y)^2005](/uploads/image/z/13889861-53-1.jpg?t=x2%2B2y%5E2-2x%2B4y%5E2%3D-3+%E6%B1%82%28x%2By%29%5E2005)
x2+2y^2-2x+4y^2=-3 求(x+y)^2005
x2+2y^2-2x+4y^2=-3 求(x+y)^2005
x2+2y^2-2x+4y^2=-3 求(x+y)^2005
x^2+2y^2-2x+4y=-3
x^2+2y^2-2x+4y+3=0
x^2-2x+1+2y^2+4y+2=0
(x-1)^2+2(y+1)^2=0
x-1=0 x=1
y+1=0 y=-1
(x+y)^2005=0^2005=0
式子写错了吧?第二项和第四项明明是同类项,为什么不合并?
拜托把式子打好一点,不会打平方 写汉字也行!