已知a1=1,an+1=an²-2an+2.①证:{log2(a-1)}为等比数列.②求ann+1为右下角角码
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![已知a1=1,an+1=an²-2an+2.①证:{log2(a-1)}为等比数列.②求ann+1为右下角角码](/uploads/image/z/14361692-68-2.jpg?t=%E5%B7%B2%E7%9F%A5a1%3D1%2Can%2B1%3Dan%26sup2%3B-2an%2B2.%E2%91%A0%E8%AF%81%EF%BC%9A%EF%BD%9Blog2%EF%BC%88a-1%EF%BC%89%EF%BD%9D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97.%E2%91%A1%E6%B1%82ann%2B1%E4%B8%BA%E5%8F%B3%E4%B8%8B%E8%A7%92%E8%A7%92%E7%A0%81)
已知a1=1,an+1=an²-2an+2.①证:{log2(a-1)}为等比数列.②求ann+1为右下角角码
已知a1=1,an+1=an²-2an+2.①证:{log2(a-1)}为等比数列.②求an
n+1为右下角角码
已知a1=1,an+1=an²-2an+2.①证:{log2(a-1)}为等比数列.②求ann+1为右下角角码
an+1 -1=(an -1)²
log2(an-1)=log2(an-1 -1)²
=2log2(an-1 -1)
所以{log2(an -1)}为等比数列
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