规定一种新运算a*b等于(a+1)(b+1)NO.1计算:(-3)*(-2)与(-2)*(-3),此运算满足交换律吗?NO.2计算【(-4)*(-3)】*(-2)与(-4)*【(-3)*(-2)】,此运算满足结合律吗?那位大师帮
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![规定一种新运算a*b等于(a+1)(b+1)NO.1计算:(-3)*(-2)与(-2)*(-3),此运算满足交换律吗?NO.2计算【(-4)*(-3)】*(-2)与(-4)*【(-3)*(-2)】,此运算满足结合律吗?那位大师帮](/uploads/image/z/15055527-39-7.jpg?t=%E8%A7%84%E5%AE%9A%E4%B8%80%E7%A7%8D%E6%96%B0%E8%BF%90%E7%AE%97a%2Ab%E7%AD%89%E4%BA%8E%EF%BC%88a%2B1%EF%BC%89%EF%BC%88b%2B1%EF%BC%89NO.1%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%88-3%EF%BC%89%2A%EF%BC%88-2%EF%BC%89%E4%B8%8E%EF%BC%88-2%EF%BC%89%2A%EF%BC%88-3%EF%BC%89%2C%E6%AD%A4%E8%BF%90%E7%AE%97%E6%BB%A1%E8%B6%B3%E4%BA%A4%E6%8D%A2%E5%BE%8B%E5%90%97%3FNO.2%E8%AE%A1%E7%AE%97%E3%80%90%EF%BC%88-4%EF%BC%89%2A%EF%BC%88-3%EF%BC%89%E3%80%91%2A%EF%BC%88-2%EF%BC%89%E4%B8%8E%EF%BC%88-4%EF%BC%89%2A%E3%80%90%EF%BC%88-3%EF%BC%89%2A%EF%BC%88-2%EF%BC%89%E3%80%91%2C%E6%AD%A4%E8%BF%90%E7%AE%97%E6%BB%A1%E8%B6%B3%E7%BB%93%E5%90%88%E5%BE%8B%E5%90%97%3F%E9%82%A3%E4%BD%8D%E5%A4%A7%E5%B8%88%E5%B8%AE)
规定一种新运算a*b等于(a+1)(b+1)NO.1计算:(-3)*(-2)与(-2)*(-3),此运算满足交换律吗?NO.2计算【(-4)*(-3)】*(-2)与(-4)*【(-3)*(-2)】,此运算满足结合律吗?那位大师帮
规定一种新运算a*b等于(a+1)(b+1)NO.1计算:(-3)*(-2)与(-2)*(-3),此运算满足交换律吗?
NO.2计算【(-4)*(-3)】*(-2)与(-4)*【(-3)*(-2)】,此运算满足结合律吗?
那位大师帮我回答一下.
规定一种新运算a*b等于(a+1)(b+1)NO.1计算:(-3)*(-2)与(-2)*(-3),此运算满足交换律吗?NO.2计算【(-4)*(-3)】*(-2)与(-4)*【(-3)*(-2)】,此运算满足结合律吗?那位大师帮
NO.1
(-3)*(-2)=(-3+1)(-2+1)=2
(-2)*(-3)=(-2+1)(-3+1)=2
此运算满足交换律
NO.2
【(-4)*(-3)】*(-2)=[(-4+1)(-3+1)]*(-2)
=6*(-2)=(6+1)(-2+1)=7
(-4)*【(-3)*(-2)】=(-4)*[(-3+1)(-2+1)]=(-4)*2=(-4+1)(2+1)=-9
此运算不满足结合律
(-3)*(-2)=(-3+1)x(-2+1)=2
(-2)*(-3)=(-2+1)x(-3+1)=2,
所以:此运算满足交换律
【(-4)*(-3)】*(-2)=【(-4+1)x(-3+1)】*(-2)=(6+1)x(-2+1)= -7
(-4)*【(-3)*(-2)】=(-4)*【(-3+1)x(-2+1)】=(-4+1)x(2+1)= -9,
所以:此...
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(-3)*(-2)=(-3+1)x(-2+1)=2
(-2)*(-3)=(-2+1)x(-3+1)=2,
所以:此运算满足交换律
【(-4)*(-3)】*(-2)=【(-4+1)x(-3+1)】*(-2)=(6+1)x(-2+1)= -7
(-4)*【(-3)*(-2)】=(-4)*【(-3+1)x(-2+1)】=(-4+1)x(2+1)= -9,
所以:此运算不满足结合律
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