已知x(x-1)-(x^2-y)=-3,求(2分之x^2+y^2)-xy的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 11:40:37
![已知x(x-1)-(x^2-y)=-3,求(2分之x^2+y^2)-xy的值](/uploads/image/z/1630085-5-5.jpg?t=%E5%B7%B2%E7%9F%A5x%28x-1%29-%28x%5E2-y%29%3D-3%2C%E6%B1%82%282%E5%88%86%E4%B9%8Bx%5E2%2By%5E2%29-xy%E7%9A%84%E5%80%BC)
已知x(x-1)-(x^2-y)=-3,求(2分之x^2+y^2)-xy的值
已知x(x-1)-(x^2-y)=-3,求(2分之x^2+y^2)-xy的值
已知x(x-1)-(x^2-y)=-3,求(2分之x^2+y^2)-xy的值
x(x-1)-(x^2-y)=-3
x ^2x-x-x^2+y=-3
-x+y=-3
x-y=3
原式=(x^2-2xy+y^2)/2
=(x-y)^2/2
=9/2
看UFO