当x取________是,多项式x²+4x+6取得最小值是_________.已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.(2001³-2*2001²-1999)/(2001³+2001²-2002)
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![当x取________是,多项式x²+4x+6取得最小值是_________.已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.(2001³-2*2001²-1999)/(2001³+2001²-2002)](/uploads/image/z/1637103-39-3.jpg?t=%E5%BD%93x%E5%8F%96________%E6%98%AF%2C%E5%A4%9A%E9%A1%B9%E5%BC%8Fx%26%23178%3B%2B4x%2B6%E5%8F%96%E5%BE%97%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF_________.%E5%B7%B2%E7%9F%A5x%E3%80%81y%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E4%B8%94%EF%BC%88x%2B2%EF%BC%89%26%23178%3B-%EF%BC%88y%2B2%EF%BC%89%26%23178%3B%3D4%2C%E5%88%99x%3D________%2Cy%3D_________.%EF%BC%882001%26%23179%3B-2%2A2001%26%23178%3B-1999%EF%BC%89%2F%EF%BC%882001%26%23179%3B%2B2001%26%23178%3B-2002%EF%BC%89)
当x取________是,多项式x²+4x+6取得最小值是_________.已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.(2001³-2*2001²-1999)/(2001³+2001²-2002)
当x取________是,多项式x²+4x+6取得最小值是_________.
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.
(2001³-2*2001²-1999)/(2001³+2001²-2002)
当x取________是,多项式x²+4x+6取得最小值是_________.已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.(2001³-2*2001²-1999)/(2001³+2001²-2002)
1、-2 2
2、1/2 -1/2
3、
[2001²(2001-2)-1999]/(2001²(2001+1)-2002]
=(2001²*1999-1999)/(2001²*2002-2002)
=1999(2001²-1)/2002(2001²-1)
=1999/2002
当x取____-2____是,多项式x²+4x+6取得最小值是_2________.
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.
(x+y+4)(x-y)=4
4(x-y)=4
x-y=1
x+y=0
所以
x=1/2,y=-1/2
(2001...
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当x取____-2____是,多项式x²+4x+6取得最小值是_2________.
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=________,y=_________.
(x+y+4)(x-y)=4
4(x-y)=4
x-y=1
x+y=0
所以
x=1/2,y=-1/2
(2001³-2*2001²-1999)/(2001³+2001²-2002)
=1
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当x取__-2______是,多项式x²+4x+6取得最小值是_(x+2)²+2=2________.
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=_1/2_______,y=___-1/2______.
(2001³-2*2001²-1999)/(2001³+2001²-2002)<...
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当x取__-2______是,多项式x²+4x+6取得最小值是_(x+2)²+2=2________.
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=_1/2_______,y=___-1/2______.
(2001³-2*2001²-1999)/(2001³+2001²-2002)
=(2001²×(2001-2)-1999)/(2001²×(2001+1)-2002)
=1999×(2001²-1)/(2002×(2001²-1))
=1999/2002;
收起
x²+4x+6
=(x+2)^2+2
当x取____-2____是,多项式x²+4x+6取得最小值是___2______.
x、y互为相反数
y=-x
(x+2)²-(y+2)²=4
(x+2)^2-(-x+2)^2=4
x^2+4x+4-(x^2-4x+4)=4
x^2+4x+4-...
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x²+4x+6
=(x+2)^2+2
当x取____-2____是,多项式x²+4x+6取得最小值是___2______.
x、y互为相反数
y=-x
(x+2)²-(y+2)²=4
(x+2)^2-(-x+2)^2=4
x^2+4x+4-(x^2-4x+4)=4
x^2+4x+4-x^2+4x-4=4
8x=4
x=1/2
y=-x=-1/2
已知x、y互为相反数,且(x+2)²-(y+2)²=4,则x=___1/2_____,y=____-1/2_____.
(2001³-2*2001²-1999)/(2001³+2001²-2002)
(2001²(2001-2)-1999)/(2001²(2001+1)-2002)
=(2001²*1999-1999)/(2001²*2002-2002)
=1999(2001²-1)/2002(2001²-1)
=1999/2002
收起