2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 10:45:00
![2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)](/uploads/image/z/175028-68-8.jpg?t=2%5Cx%2B2-%281%29%5Cx-2%3D0%E8%A7%A3%E6%96%B9%E7%A8%8B%E5%B9%B6%E9%AA%8C%E7%AE%97+%287%5Cx%5E2%2Bx%29%2B%283%5Cx%5E2-x%29%3D%286%5Cx%5E2-1%29)
2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)
2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)
2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)
1、两边乘以(x+2)(x-2)得
2(x-2)-(x+2)=0
2x-4-x-2=0
∴x=6
检验:x=6是方程的解
∴方程的解是x=6
2、两边乘以x(x+1)(x-1)得
7(x-1)+3(x+1)=6x
7x-7+3x+3=6x
4x=4
x=1
检验:x=1是增根
∴方程没有解