log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 16:14:25
![log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)](/uploads/image/z/1767660-60-0.jpg?t=log1%5C2%288-2%E7%9A%84x%E6%AC%A1%E6%96%B9%29%3Elog1%2F2%284%E7%9A%84x%E6%AC%A1%E6%96%B9-2%E7%9A%84x%2B2%E6%AC%A1%E6%96%B9-2%29)
log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
log1\2(8-2的x次方)>log1/2(4的x次方-2的x+2次方-2)
由于函数y=log1/2 x是一个减函数,则有:00
2^x>5
x>log2(5)
综上,解集是log2(5)