lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)求极限 谢谢 需要详细过程说明
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![lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)求极限 谢谢 需要详细过程说明](/uploads/image/z/1814923-19-3.jpg?t=lim++n%E8%B6%8B%E5%90%91%E6%97%A0%E7%A9%B7%E5%A4%A7+++%281%2B1%2F2%2B1%2F4%2B...%2B1%2F2%E7%9A%84%E6%AC%A1%E6%96%B9%29%E6%B1%82%E6%9E%81%E9%99%90+++++++%E8%B0%A2%E8%B0%A2++++++%E9%9C%80%E8%A6%81%E8%AF%A6%E7%BB%86%E8%BF%87%E7%A8%8B%E8%AF%B4%E6%98%8E)
lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)求极限 谢谢 需要详细过程说明
lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)
求极限 谢谢 需要详细过程说明
lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)求极限 谢谢 需要详细过程说明
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lim (1+1/2n)^n n趋向于无穷大
lim√1+1/n^2 n趋向于无穷大
lim n趋向无穷大3n^3+n^2-3/4n^3+2n+1
lim(1+1/n+1)^n.趋向无穷大
紧急:求 lim n*sin(π(n^2+2)^0.5)*(-1)^n,n趋向无穷大;
n趋向于无穷大,lim n[ln(n+2)-ln(n+1)],
求lim(1+1/n+2)=n->0的极限?(n趋向无穷大)
证明lim(n/(n^2+1))=0(n趋向于无穷大)
lim(n^2(cos1/n-1))(n趋向于无穷大)
证明 lim(1-1/2^n)=1 n趋向于无穷大
lim(1-1/2^n)=1 n趋向于无穷大
求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方)
lim n趋向无穷大(3^n+2^n)/(3^(n+1)-2^(n+1))=?
lim n趋向无穷大 (2^3n-3^2n-1)/(2^3n+3^2n)=?
用夹逼准则求lim(1/n^2+1/(n^2+1)+...+1/(2n)^2),n趋向于无穷大
lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大
lim(x趋向无穷大)[1+2/(x+2)]^(x+2)
lim x趋向无穷大 (1+2/x)^x=?