已知x2+y2-6x+4y+13=0,求2x+3y
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已知x2+y2-6x+4y+13=0,求2x+3y
已知x2+y2-6x+4y+13=0,求2x+3y
已知x2+y2-6x+4y+13=0,求2x+3y
即(x²-6x+9)+(y²+4y+4)=0
(x-3)²+(y+2)²=0
所以x-3=y+2=0
所以x=3,y=-2
所以2x+3y
=6-6
=0
x2+y2-6x+4y+13=0
(x-3)²+(y+2)²=0
x=3,y=-2
2x+3y
=2×3+3×(-2)
=0
x^2+y^2-6x+4y+13=0
(x-3)^2+(y+2)^2=0
x=3 y=-2
2x+3y=2*3-2*3=0