f(x)=(a-2)x²+(a-1)x+3是偶数,求实数a的值?求函数f(x)的单调递增区间?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 05:58:51
![f(x)=(a-2)x²+(a-1)x+3是偶数,求实数a的值?求函数f(x)的单调递增区间?](/uploads/image/z/1988864-8-4.jpg?t=f%28x%29%3D%28a-2%29x%26%23178%3B%2B%EF%BC%88a-1%29x%2B3%E6%98%AF%E5%81%B6%E6%95%B0%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC%3F%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%3F)
f(x)=(a-2)x²+(a-1)x+3是偶数,求实数a的值?求函数f(x)的单调递增区间?
f(x)=(a-2)x²+(a-1)x+3是偶数,求实数a的值?求函数f(x)的单调递增区间?
f(x)=(a-2)x²+(a-1)x+3是偶数,求实数a的值?求函数f(x)的单调递增区间?
是偶函数吧,f(x)=f(-x),得a=1
单调递增区间:当a>2时,x》0;当a<2时,x《0