若a³+b³=35,a²b-ab²=6,则(a³-b³)+(3ab²-a²b)-2(a²b-b³)
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![若a³+b³=35,a²b-ab²=6,则(a³-b³)+(3ab²-a²b)-2(a²b-b³)](/uploads/image/z/1994464-64-4.jpg?t=%E8%8B%A5a%26%23179%3B%2Bb%26%23179%3B%3D35%2Ca%26%23178%3Bb-ab%26%23178%3B%3D6%2C%E5%88%99%EF%BC%88a%26%23179%3B-b%26%23179%3B%EF%BC%89%2B%EF%BC%883ab%26%23178%3B-a%26%23178%3Bb%EF%BC%89-2%EF%BC%88a%26%23178%3Bb-b%26%23179%3B%EF%BC%89)
若a³+b³=35,a²b-ab²=6,则(a³-b³)+(3ab²-a²b)-2(a²b-b³)
若a³+b³=35,a²b-ab²=6,则(a³-b³)+(3ab²-a²b)-2(a²b-b³)
若a³+b³=35,a²b-ab²=6,则(a³-b³)+(3ab²-a²b)-2(a²b-b³)
(a³-b³)+(3ab²-a²b)-2(a²b-b³)
= a³ -b³ + 3ab² -a²b - 2a²b + 2b³
= a³ + b³ + 3ab² - 3ab²
= a³ + b³ + 3( a²b - ab² )
= 35 + 3×6
= 53