若4x²-4x+9y²-12y+5=0,求(x-3y)²-(x+3y)²的值
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若4x²-4x+9y²-12y+5=0,求(x-3y)²-(x+3y)²的值
若4x²-4x+9y²-12y+5=0,求(x-3y)²-(x+3y)²的值
若4x²-4x+9y²-12y+5=0,求(x-3y)²-(x+3y)²的值
4x²-4x+9y²-12y+5=0,
==>(2x-1)^2+(3y-2)^2=0
x=0.5;y=2/3
(x-3y)²-(x+3y)²=-6xy-6xy=-12xy=-4