已知y=x平方-9分之x²+6x+9÷x²-3x分之x+3-x+3,试说明不论x为任何有意义的值,y的值均不变
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![已知y=x平方-9分之x²+6x+9÷x²-3x分之x+3-x+3,试说明不论x为任何有意义的值,y的值均不变](/uploads/image/z/2488649-41-9.jpg?t=%E5%B7%B2%E7%9F%A5y%3Dx%E5%B9%B3%E6%96%B9-9%E5%88%86%E4%B9%8Bx%26%23178%3B%2B6x%2B9%C3%B7x%26%23178%3B-3x%E5%88%86%E4%B9%8Bx%2B3-x%2B3%2C%E8%AF%95%E8%AF%B4%E6%98%8E%E4%B8%8D%E8%AE%BAx%E4%B8%BA%E4%BB%BB%E4%BD%95%E6%9C%89%E6%84%8F%E4%B9%89%E7%9A%84%E5%80%BC%2Cy%E7%9A%84%E5%80%BC%E5%9D%87%E4%B8%8D%E5%8F%98)
已知y=x平方-9分之x²+6x+9÷x²-3x分之x+3-x+3,试说明不论x为任何有意义的值,y的值均不变
已知y=x平方-9分之x²+6x+9÷x²-3x分之x+3-x+3,试说明不论x为任何有意义的值,y的值均不变
已知y=x平方-9分之x²+6x+9÷x²-3x分之x+3-x+3,试说明不论x为任何有意义的值,y的值均不变
y=(x^2+6x+9)/(x^2-9)÷(x+3)/(x^2-3x)-x+3
=(x+3)^2/(x-3)(x+3)*(x^2-3x)/(x+3)/-x+3
=(x^2-3x)/(x-3)-x+3
=x(x-3)/(x-3)-x+3
=x-x+3
=3
所以不论x为任何有意义的值,y的值均不变