y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 18:33:15
![y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?](/uploads/image/z/2494778-50-8.jpg?t=y%3Dsin%282x%2B%CF%80%2F6%29%2Bcos%282x%2B%CF%80%2F3%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E5%92%8C%E6%9C%80%E5%A4%A7%E5%80%BC%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6y%3Dsin%282x%2B%CF%80%2F6%29%2Bcos%282x%2B%CF%80%2F3%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E5%92%8C%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF%3F)
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
sinα+sinβ=2sin[(α+β)/2]cos[(α-β)/2]
y=sin(2x+π/6)+cos(2x+π/3)
=sin(2x+π/6)+sin[π/2-(2x+π/3)]
=sin(2x+π/6)+sin(-2x+π/6)
=2sin(π/6)cos(2x)
=cos(2x)
y=sin(2x+π/6)+cos(2x+π/3)的最大值=1
最小正周期T=2∏/2=∏.