2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
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![2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5](/uploads/image/z/2519403-51-3.jpg?t=2x%2B3y%2F2%2B3x%2B2y%2F5%3D11%2F3%2C3%282x%2B3y%EF%BC%89%2F2%3D6%EF%BC%883x%2B2y%EF%BC%89%2F7%2B2.5%2C%E6%B1%82%E6%95%99%E5%95%8A%3D+%3D2x%2B3y%2F2%2B3x%2B2y%2F5%3D11%2F3+%2C3%282x%2B3y%EF%BC%89%2F2%3D6%EF%BC%883x%2B2y%EF%BC%89%2F7%2B2.5)
2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =
2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
题目中第一式是不是应该是:(2x+3y)/2+(3x+2y)/5=11/3 , 否则这样出没意义.
如果是这样的话,解法如下:
15(2x+3y)+6(3x+2y)=110, 21(2x+3y)-12(3x+2y)=35
48x+57y=110,6x+39y=35
加减法解得:x=3/2, y=2/3
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
化简:5(x-y)+2(x+y)-3(x-y)
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
(x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
(2x-3y)-(5x-y)
(2X-3y)-(5x-y)
(2x-5y)(3x+y)
(x+y)(2x-3y)=?
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)