已知a²+ab=3,b²+ab=-2,(1)求a²+2ab+b² (2)a²-b²
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已知a²+ab=3,b²+ab=-2,(1)求a²+2ab+b² (2)a²-b²
已知a²+ab=3,b²+ab=-2,(1)求a²+2ab+b² (2)a²-b²
已知a²+ab=3,b²+ab=-2,(1)求a²+2ab+b² (2)a²-b²
(1)
两式相加 a²+2ab+b²=3-2=1
(2)
两式相减 a²-b²=3-(-2)=5
(1)
a²+ab=3 1
b²+ab=-2 2
1式+2式得
a²+2ab+b² =3-2=1
(2)
1式-2式得
a²-b²=3-(-2)=5