解不等式:1+log1/2(x^2-x-2)>log1/2(x-1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 18:17:30
![解不等式:1+log1/2(x^2-x-2)>log1/2(x-1)](/uploads/image/z/2538134-62-4.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%EF%BC%9A1%2Blog1%2F2%28x%5E2-x-2%29%3Elog1%2F2%28x-1%29)
解不等式:1+log1/2(x^2-x-2)>log1/2(x-1)
解不等式:1+log1/2(x^2-x-2)>log1/2(x-1)
解不等式:1+log1/2(x^2-x-2)>log1/2(x-1)
原不等式可化为log1/2(x^2-x-2)*1/2>log1/2(x-1)
因为y=log1/2x在定义域内是减函数,
所以x^2-x-2>0
x-1>0
(x^2-x-2)*1/21
0