若a+b+c+3=2(根号a + 根号b+1 + 根号c-1),求a^2+b^2+c^2的值
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![若a+b+c+3=2(根号a + 根号b+1 + 根号c-1),求a^2+b^2+c^2的值](/uploads/image/z/2655140-68-0.jpg?t=%E8%8B%A5a%2Bb%2Bc%2B3%3D2%28%E6%A0%B9%E5%8F%B7a+%2B+%E6%A0%B9%E5%8F%B7b%2B1+%2B+%E6%A0%B9%E5%8F%B7c-1%29%2C%E6%B1%82a%5E2%2Bb%5E2%2Bc%5E2%E7%9A%84%E5%80%BC)
若a+b+c+3=2(根号a + 根号b+1 + 根号c-1),求a^2+b^2+c^2的值
若a+b+c+3=2(根号a + 根号b+1 + 根号c-1),求a^2+b^2+c^2的值
若a+b+c+3=2(根号a + 根号b+1 + 根号c-1),求a^2+b^2+c^2的值
a+b+c+3=2(根号a + 根号b+1 + 根号c-1),
==>
(根号a -1)^2+ (根号b+1 -1)^2+ (根号c-1 -1)^2=0
==>
根号a -1=0,根号b+1 -1 =0;根号c-1 -1=0
a=1 b=0 c=2
a^2+b^2+c^2=1+4=5