已知:a²+b²-2a+4b+5=0,求a²-b²/a²+2ab+b²的值.
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已知:a²+b²-2a+4b+5=0,求a²-b²/a²+2ab+b²的值.
已知:a²+b²-2a+4b+5=0,求a²-b²/a²+2ab+b²的值.
已知:a²+b²-2a+4b+5=0,求a²-b²/a²+2ab+b²的值.
a²+b²-2a+4b+5=0
∴(a²-2a+1)+(b²+4b+4)=0
∴(a-1)²+(b+2)²=0
∵(a-1)²≥0,(b+2)²≥0
∴a=1,b=-2
∴a²-b²/a²+2ab+b²
=(a-b)(a+b)/(a+b)²
=(a-b)/(a+b)
=(1+2)/(1-2)
=3/(-1)
=-3
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