(1+2+3+……+100)+(1+2^2+3^2+……+50^2)+(1+1/2+1/3+……+1/10) 怎样编程?#include main(){int i=1;float s1=0,s2=0,s3=0;float j,sum;sum=s1+s2+s3;for(i=1;i
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![(1+2+3+……+100)+(1+2^2+3^2+……+50^2)+(1+1/2+1/3+……+1/10) 怎样编程?#include main(){int i=1;float s1=0,s2=0,s3=0;float j,sum;sum=s1+s2+s3;for(i=1;i](/uploads/image/z/2796296-32-6.jpg?t=%EF%BC%881%2B2%2B3%2B%E2%80%A6%E2%80%A6%2B100%EF%BC%89%2B%EF%BC%881%2B2%5E2%2B3%5E2%2B%E2%80%A6%E2%80%A6%2B50%5E2%EF%BC%89%2B%EF%BC%881%2B1%2F2%2B1%2F3%2B%E2%80%A6%E2%80%A6%2B1%2F10%EF%BC%89+%E6%80%8E%E6%A0%B7%E7%BC%96%E7%A8%8B%3F%23include+main%28%29%7Bint+i%3D1%3Bfloat+s1%3D0%2Cs2%3D0%2Cs3%3D0%3Bfloat+j%2Csum%3Bsum%3Ds1%2Bs2%2Bs3%3Bfor%28i%3D1%3Bi)
(1+2+3+……+100)+(1+2^2+3^2+……+50^2)+(1+1/2+1/3+……+1/10) 怎样编程?#include main(){int i=1;float s1=0,s2=0,s3=0;float j,sum;sum=s1+s2+s3;for(i=1;i
(1+2+3+……+100)+(1+2^2+3^2+……+50^2)+(1+1/2+1/3+……+1/10) 怎样编程?
#include
main()
{
int i=1;
float s1=0,s2=0,s3=0;
float j,sum;
sum=s1+s2+s3;
for(i=1;i
(1+2+3+……+100)+(1+2^2+3^2+……+50^2)+(1+1/2+1/3+……+1/10) 怎样编程?#include main(){int i=1;float s1=0,s2=0,s3=0;float j,sum;sum=s1+s2+s3;for(i=1;i
将 sum=s1+s2+s3; 放在printf("sum=%f\n",sum); 之前 你试下程序还是好久前学的
(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+………+(1/1+2+3+………+100)
1+2+3……+99+100+99+98+……+3+2+1=( )
1+1+2+3…………...+100等于?
1+1+2+3……+100
1+2+3+…………+100+101等于
-1-2-3-……-99-100
1+2+3+……+99+100
1+2+3+……+100=?
1+2+3……+100+101
1+2+3……+100=?
1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+……+1/(1+2+3+……+100)=?.
(2+4+6+……+100)-(1+3+5+……+99)简便计算
(100+98+96+……+4+2)-(99+97+95+……+3+1)
(1+1)×(1+2)×(1+3)……(1+100)
1 +(1+2)/1+(1+2+3)/1+……+(+2+3+4+5+…+100)/1最后打错了,是(1+2+3…………+100)/1
1/(1+2) + 1/(1+2+3) + 1/(1+2+3+4)……+1/(1+2+3+4+……+99+100)=( )
(1-1/2^2)(1-1/3^2)(1-1/4^2)……(1-1/100^2)=( )
(-1)+2+(-3)+4+……+(-99)+100 (-1)+2+(-3)+4+……+(-99)+100