x²ax-12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?前面打错了,改成a+2b+3c=12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?
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![x²ax-12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?前面打错了,改成a+2b+3c=12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?](/uploads/image/z/2803113-9-3.jpg?t=x%26%23178%3Bax-12%2C%E4%B8%94a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%3Dab%2Bbc%2Bca%2C%E5%88%99a%2Bb%26%23178%3B%2Bc%26%23179%3B%3D%3F%E5%89%8D%E9%9D%A2%E6%89%93%E9%94%99%E4%BA%86%EF%BC%8C%E6%94%B9%E6%88%90a%2B2b%2B3c%3D12%2C%E4%B8%94a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%3Dab%2Bbc%2Bca%2C%E5%88%99a%2Bb%26%23178%3B%2Bc%26%23179%3B%3D%EF%BC%9F)
x²ax-12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?前面打错了,改成a+2b+3c=12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?
x²ax-12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?
前面打错了,改成a+2b+3c=12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?
x²ax-12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?前面打错了,改成a+2b+3c=12,且a²+b²+c²=ab+bc+ca,则a+b²+c³=?
2a²+2b²+2c²=2ab+2bc+2ca
(a-b)^2+(b-c)^2+(a-c)^2=0
a-b=0,a-c=0,b-c=0
a=b=c
a+2b+3c=12
a=b=c=2
a+b^2+c^3=2+4+8=14