(x+2根号xy+y)除以(根号x+根号y)把它根式有理化
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![(x+2根号xy+y)除以(根号x+根号y)把它根式有理化](/uploads/image/z/3006702-54-2.jpg?t=%28x%2B2%E6%A0%B9%E5%8F%B7xy%2By%29%E9%99%A4%E4%BB%A5%28%E6%A0%B9%E5%8F%B7x%2B%E6%A0%B9%E5%8F%B7y%29%E6%8A%8A%E5%AE%83%E6%A0%B9%E5%BC%8F%E6%9C%89%E7%90%86%E5%8C%96)
(x+2根号xy+y)除以(根号x+根号y)把它根式有理化
(x+2根号xy+y)除以(根号x+根号y)把它根式有理化
(x+2根号xy+y)除以(根号x+根号y)把它根式有理化
=(√x+√y)²/(√x+√y)
=√x+√y
(根号x+根号y)²/(根号x+根号y)=(根号x+根号y)
(x+2根号xy+y)除以(根号x+根号y)
=(根号x+根号y)²/(根号x+根号y)
=根号x+根号y
(x+2根号xy+y)除以(根号x+根号y)
=(根号x+根号y)2/(根号x+根号y)
=根号x+根号y