an=n*2^(n-1),数列bn前n项和为Tn,bn=((an+1)-1)/((an+1)+2),求证:n-3/2<Tn<n-1/4.急求高手解答,非常感激.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 18:26:18
![an=n*2^(n-1),数列bn前n项和为Tn,bn=((an+1)-1)/((an+1)+2),求证:n-3/2<Tn<n-1/4.急求高手解答,非常感激.](/uploads/image/z/3146727-39-7.jpg?t=an%3Dn%2A2%5E%EF%BC%88n-1%EF%BC%89%2C%E6%95%B0%E5%88%97bn%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BATn%2Cbn%3D%EF%BC%88%EF%BC%88an%2B1%EF%BC%89-1%EF%BC%89%2F%EF%BC%88%EF%BC%88an%2B1%EF%BC%89%2B2%EF%BC%89%2C%E6%B1%82%E8%AF%81%EF%BC%9An-3%2F2%EF%BC%9CTn%EF%BC%9Cn-1%2F4.%E6%80%A5%E6%B1%82%E9%AB%98%E6%89%8B%E8%A7%A3%E7%AD%94%2C%E9%9D%9E%E5%B8%B8%E6%84%9F%E6%BF%80.)
an=n*2^(n-1),数列bn前n项和为Tn,bn=((an+1)-1)/((an+1)+2),求证:n-3/2<Tn<n-1/4.急求高手解答,非常感激.
an=n*2^(n-1),数列bn前n项和为Tn,bn=((an+1)-1)/((an+1)+2),求证:n-3/2<Tn<n-1/4.
急求高手解答,非常感激.
an=n*2^(n-1),数列bn前n项和为Tn,bn=((an+1)-1)/((an+1)+2),求证:n-3/2<Tn<n-1/4.急求高手解答,非常感激.