已知x+2y=0(x≠0),求分式x²-xy分之2xy+y²的值
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![已知x+2y=0(x≠0),求分式x²-xy分之2xy+y²的值](/uploads/image/z/318772-28-2.jpg?t=%E5%B7%B2%E7%9F%A5x%2B2y%3D0%28x%E2%89%A00%29%2C%E6%B1%82%E5%88%86%E5%BC%8Fx%26%23178%3B-xy%E5%88%86%E4%B9%8B2xy%2By%26%23178%3B%E7%9A%84%E5%80%BC)
已知x+2y=0(x≠0),求分式x²-xy分之2xy+y²的值
已知x+2y=0(x≠0),求分式x²-xy分之2xy+y²的值
已知x+2y=0(x≠0),求分式x²-xy分之2xy+y²的值
x+2y=0
x=-2y
(2xy+y²)/(x²-xy)
=y(2x+y)/[x(x-y)]
=y(-4y+y)/[-2y(-3y)]
=-3y²/6y²
=-1/2
由x+2y=0得x=-2y,x²-xy分之2xy+y²可化简为6y²分之-3y²,最终结果得-2分之1