实数ab满足a²+4b²+2a-4b+2=0 (1)求ab的值 (2)方程6(1+b)x²=6+2a的根
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![实数ab满足a²+4b²+2a-4b+2=0 (1)求ab的值 (2)方程6(1+b)x²=6+2a的根](/uploads/image/z/3706411-67-1.jpg?t=%E5%AE%9E%E6%95%B0ab%E6%BB%A1%E8%B6%B3a%26%23178%3B%2B4b%26%23178%3B%2B2a-4b%2B2%3D0+%EF%BC%881%EF%BC%89%E6%B1%82ab%E7%9A%84%E5%80%BC+%EF%BC%882%EF%BC%89%E6%96%B9%E7%A8%8B6%EF%BC%881%2Bb%EF%BC%89x%26%23178%3B%3D6%2B2a%E7%9A%84%E6%A0%B9)
实数ab满足a²+4b²+2a-4b+2=0 (1)求ab的值 (2)方程6(1+b)x²=6+2a的根
实数ab满足a²+4b²+2a-4b+2=0 (1)求ab的值 (2)方程6(1+b)x²=6+2a的根
实数ab满足a²+4b²+2a-4b+2=0 (1)求ab的值 (2)方程6(1+b)x²=6+2a的根
原式= a²+2a+1+4b²-4b+1
=(a+1)² +(2b-1)² =0
所以a+1=0,2b-1=0
所以a=-1 b=1/2
(a+1)²+(2b-1)²=0
a=-1,b=1/2