分解因式(x²+5x+3)(x²+5x-23)+k=(x²+5x-10)²后,求k
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 16:50:06
![分解因式(x²+5x+3)(x²+5x-23)+k=(x²+5x-10)²后,求k](/uploads/image/z/3767163-51-3.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%88x%26%23178%3B%2B5x%2B3%EF%BC%89%EF%BC%88x%26%23178%3B%2B5x-23%EF%BC%89%2Bk%3D%EF%BC%88x%26%23178%3B%2B5x-10%EF%BC%89%26%23178%3B%E5%90%8E%2C%E6%B1%82k)
分解因式(x²+5x+3)(x²+5x-23)+k=(x²+5x-10)²后,求k
分解因式(x²+5x+3)(x²+5x-23)+k=(x²+5x-10)²后,求k
分解因式(x²+5x+3)(x²+5x-23)+k=(x²+5x-10)²后,求k
左式=(x²+5x)²-20(x²+5x)-69+k
右式=(x²+5x)²-20(x²+5x)+100
∴-69+k=100
得:k=169