试求代数式(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²的值,其中X,Y是二元一次方程组{2X-3Y=13的解.{3X+2Y=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/22 22:50:25
![试求代数式(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²的值,其中X,Y是二元一次方程组{2X-3Y=13的解.{3X+2Y=0](/uploads/image/z/3809999-47-9.jpg?t=%E8%AF%95%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%882X%2BY%29%26%23178%3B-2%282X%2BY%29%28X-Y%29%2B%28X-Y%29%26%23178%3B%E7%9A%84%E5%80%BC%2C%E5%85%B6%E4%B8%ADX%2CY%E6%98%AF%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%BB%84%EF%BD%9B2X-3Y%3D13%E7%9A%84%E8%A7%A3.%EF%BD%9B3X%2B2Y%3D0)
试求代数式(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²的值,其中X,Y是二元一次方程组{2X-3Y=13的解.{3X+2Y=0
试求代数式(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²的值,其中X,Y是二元一次方程组
{2X-3Y=13的解.{3X+2Y=0
试求代数式(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²的值,其中X,Y是二元一次方程组{2X-3Y=13的解.{3X+2Y=0
2X-3Y=13,3X+2Y=0
求解出x=2,y=-3
(2X+Y)²-2(2X+Y)(X-Y)+(X-Y)²=[(2x+y)-(x-y)]²=(x+2y)²=(2-6)²=16