二次根式的题:(1+√2)²(1+√3)²(1—√2)²(1—√3)²怎么解,
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二次根式的题:(1+√2)²(1+√3)²(1—√2)²(1—√3)²怎么解,
二次根式的题:(1+√2)²(1+√3)²(1—√2)²(1—√3)²怎么解,
二次根式的题:(1+√2)²(1+√3)²(1—√2)²(1—√3)²怎么解,
:(1+√2)²(1+√3)²(1—√2)²(1—√3)²
=[(1+√2)(1-√2)]²[(1+√3)(1-√3)]²
=(1-2)²(1-3)²
=1×4
=4
原式=[(1+根号2)(1-根号2)]^2 乘(1+根号3)(1-根号3)]^2
=(1-2)^2乘(1-3)^2
=4