若sin(π+x)+cos(π/2+x)=-m,则cos(3π/2-π)+2sin(6π-x)=?
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![若sin(π+x)+cos(π/2+x)=-m,则cos(3π/2-π)+2sin(6π-x)=?](/uploads/image/z/3912609-57-9.jpg?t=%E8%8B%A5sin%28%CF%80%2Bx%29%2Bcos%28%CF%80%2F2%2Bx%29%3D-m%2C%E5%88%99cos%EF%BC%883%CF%80%2F2-%CF%80%EF%BC%89%2B2sin%EF%BC%886%CF%80-x%EF%BC%89%3D%3F)
若sin(π+x)+cos(π/2+x)=-m,则cos(3π/2-π)+2sin(6π-x)=?
若sin(π+x)+cos(π/2+x)=-m,则cos(3π/2-π)+2sin(6π-x)=?
若sin(π+x)+cos(π/2+x)=-m,则cos(3π/2-π)+2sin(6π-x)=?
sin(π+x)+cos(π/2+x)=-sinx-sinx=-m
sinx=m/2
cos(3π/2-x)+2sin(6π-x)
=-sinx-2sinx=-3sinx=-3/2m