(x+½)²(x²-x+1/4)²=?

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(x+½)²(x²-x+1/4)²=?

(x+½)²(x²-x+1/4)²=?
(x+½)²(x²-x+1/4)²=?

(x+½)²(x²-x+1/4)²=?
原式
=(x+2分之1)²(x-2分之1)²
=[x²-(2分之1)²]²
=(x²-4分之1)²
=x的4次方-2分之x²+16分之1

(x+½)²(x²-x+1/4)²=(x+½)²(x²-1/2)²=[(x+½)(x²-1/2)]²=(x-1/4)²=x^2-1/2*x+1/16

原式变为
(X+1/2)(X+1/2)(X-1/2)(X-1/2)
=(X^2-1/4)^2