观察下列各式1²=1,1²-2²=-3,1²-2²+3²=6,1²-2²+3²-4=-10照此规律,第n个等式可为?
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![观察下列各式1²=1,1²-2²=-3,1²-2²+3²=6,1²-2²+3²-4=-10照此规律,第n个等式可为?](/uploads/image/z/4015699-43-9.jpg?t=%E8%A7%82%E5%AF%9F%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F1%26%23178%3B%3D1%2C1%26%23178%3B-2%26%23178%3B%3D-3%2C1%26%23178%3B-2%26%23178%3B%2B3%26%23178%3B%3D6%2C1%26%23178%3B-2%26%23178%3B%2B3%26%23178%3B-4%3D-10%E7%85%A7%E6%AD%A4%E8%A7%84%E5%BE%8B%2C%E7%AC%ACn%E4%B8%AA%E7%AD%89%E5%BC%8F%E5%8F%AF%E4%B8%BA%3F)
观察下列各式1²=1,1²-2²=-3,1²-2²+3²=6,1²-2²+3²-4=-10照此规律,第n个等式可为?
观察下列各式1²=1,1²-2²=-3,1²-2²+3²=6,1²-2²+3²-4=-10
照此规律,第n个等式可为?
观察下列各式1²=1,1²-2²=-3,1²-2²+3²=6,1²-2²+3²-4=-10照此规律,第n个等式可为?
我把步骤卸载纸上发给你了.这图片有点大,只能压缩上传了、还望采纳啊
第n个等式可为:[(-1)^(n+1)]n(n+1)/2
(-1)的n+1方*(1+2+3+...+n),自己算吧