先化简再求值(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3),其中x=【2】怎么写啊,根本化简不鸟!
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 03:45:51
![先化简再求值(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3),其中x=【2】怎么写啊,根本化简不鸟!](/uploads/image/z/401696-8-6.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%283x-2x%26%23178%3B%29%283-2x-x%26%23178%3B%29%2F%28x%26%23178%3B%2Bx%29%282x%26%23178%3B-5x%2B3%29%2C%E5%85%B6%E4%B8%ADx%3D%E3%80%902%E3%80%91%E6%80%8E%E4%B9%88%E5%86%99%E5%95%8A%2C%E6%A0%B9%E6%9C%AC%E5%8C%96%E7%AE%80%E4%B8%8D%E9%B8%9F%21)
先化简再求值(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3),其中x=【2】怎么写啊,根本化简不鸟!
先化简再求值(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3),其中x=【2】怎么写啊,根本化简不鸟!
先化简再求值(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3),其中x=【2】怎么写啊,根本化简不鸟!
(3x-2x²)(3-2x-x²)/(x²+x)(2x²-5x+3)=x(3-2x)(3+x)(1-x)/x(x+1)(2x-3)(x-1)
=(x+3)/(x+1)=5/3
原式=x(3-2x)(x+3)(1-x)/x(x+1)(x-1)(2x-3)=(x+3)/(x+1)当x=2时,原式=5/3