分式的计算题,能做几题做几题!1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))
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![分式的计算题,能做几题做几题!1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))](/uploads/image/z/4028492-20-2.jpg?t=%E5%88%86%E5%BC%8F%E7%9A%84%E8%AE%A1%E7%AE%97%E9%A2%98%2C%E8%83%BD%E5%81%9A%E5%87%A0%E9%A2%98%E5%81%9A%E5%87%A0%E9%A2%98%211.1%2F%28x%5E2%2B3x%2B2%29%2B1%2F%28x%5E2%2B5x%2B6%29%2B1%2F%28x%5E2%2B4x%2B3%292.%5Ba%2F%28a-b%29-a%5E2%2F%28a%5E2-2ab%2Bb%5E2%29%5D%C3%B7%5Ba%2F%28a-b%29%2Ba%5E2%2F%28b%5E2-a%5E2%29%5D3.x%2B2y%2F%28x%5E2-y%5E2-z%5E2-2yz%29-x%2B2y%2F%28y%5E2%2Bz%5E2-x%5E2%2B2yz%294.b%2F%28a-b%2Bc%29%2B2a%2Bc%2F%28b-a-c%29%2Bb-c%2F%28b-a-c%29%29)
分式的计算题,能做几题做几题!1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))
分式的计算题,
能做几题做几题!
1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)
2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]
3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)
4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))
分式的计算题,能做几题做几题!1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))
1.〔1/(x+1)(x+2)〕+〔1/(x+2)(x+3)〕+〔1/(x+1)(x+3)〕=〔x+3/(x+1)(x+2)(x+3)〕+〔x+1/(x+1)(x+2)(x+3)〕+〔x+2/(x+1)(x+2)(x+3)〕=〔3x+6/(x+1)(x+2)(x+3)〕=3/(x+1)(x+3)
2.=[1/(a-b)-a/(a^2-2ab+b^2)]÷[1/(a-b)+a/(b^2-a^2)] = [1/(a-b)-a/(a-b)^2]÷[1/(a-b)-a/(a-b)(a+b)]=[(a-b-a)/(a-b)^2]÷[(a+b-a)/(a-b)(a+b)]=
[(a-b-a)/(a-b)^2]÷[(a+b-a)/(a-b)(a+b)]=[(-b)/(a-b)^2]×[(a-b)(a+b)/(+b)]=-(a+b)/(a-b)
3.原式是否为:(x+2y)/(x^2-y^2-z^2-2yz)-(x+2y)/(y^2+z^2-x^2+2yz) =(x+2y)/(x^2-y^2-z^2-2yz)+(x+2y)/(x^2-y^2-z^2-2yz) =2(x+2y)/(x^2-y^2-z^2-2yz)+(x+2y)/(x^2-y^2-z^2-2yz) =2(x+2y)/(x+y+z)(x-y-z)
4.原式是否为:b/(a-b+c)+(2a+c)/(b-a-c)+(b-c)/(b-a-c)=b/(a-b+c)+(-2a-c)/(a-b+c)+(c-b)/(a-b+c)=(b-2a-c+c-b)/(a-b+c)=-2a/(a-b+c)
1. 3/(x+1(x+3)
2.(2a-b)(a+b)/(a-b)^2
太累了 找初中生去做吧....
[3(x+2)]/[(x+1)(x+3)],(b^2-a^2)/[(a-b)^2],[2(x+2y)]/[(x+y+z)(x+y-z)],2a/(b-a-c)