-x²-6x+2-()=3x²+x+1,括号中应填的是()已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=()
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![-x²-6x+2-()=3x²+x+1,括号中应填的是()已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=()](/uploads/image/z/4355724-12-4.jpg?t=-x%26%23178%3B-6x%2B2-%28%29%3D3x%26%23178%3B%2Bx%2B1%2C%E6%8B%AC%E5%8F%B7%E4%B8%AD%E5%BA%94%E5%A1%AB%E7%9A%84%E6%98%AF%EF%BC%88%EF%BC%89%E5%B7%B2%E7%9F%A5x%26%23178%3B%2Bxy%3D3%2Cy%26%23178%3B%2Bxy%3D-2%2C%E5%88%992x%26%23178%3B-xy-3y%26%23178%3B%3D%EF%BC%88%EF%BC%89)
-x²-6x+2-()=3x²+x+1,括号中应填的是()已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=()
-x²-6x+2-()=3x²+x+1,括号中应填的是()
已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=()
-x²-6x+2-()=3x²+x+1,括号中应填的是()已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=()
-x²-6x+2-()=3x²+x+1,括号中应填的是(-4x²-7x+1)
-x²-6x+2-(3x²+x+1)
=-x²-6x+2-3x²-x-1
=-4x²-7x+1
已知x²+xy=3,y²+xy=-2,则2x²-xy-3y²=(12)
2x²-xy-3y²
=2x²+2xy-3xy-3y²
=2(x²+xy)-3(xy+y²)
=2×3-3×(-2)
=12
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