(0.25)^(-2)+8^(2/3)-(1/16)^9-0.75)-lg25-2lg2=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 06:48:07
![(0.25)^(-2)+8^(2/3)-(1/16)^9-0.75)-lg25-2lg2=?](/uploads/image/z/435588-60-8.jpg?t=%280.25%29%5E%28-2%29%2B8%5E%282%2F3%29-%281%2F16%29%5E9-0.75%29-lg25-2lg2%3D%3F)
(0.25)^(-2)+8^(2/3)-(1/16)^9-0.75)-lg25-2lg2=?
(0.25)^(-2)+8^(2/3)-(1/16)^9-0.75)-lg25-2lg2=?
(0.25)^(-2)+8^(2/3)-(1/16)^9-0.75)-lg25-2lg2=?
(1/4)^-2=16
8^2/3=4
(1/16)^(-3/4)=8
-lg25-2lg2=-(lg25+lg4)=-lg25*4=-2
所以
0.25负平方+8的3分之二平方-16分之1的0.75次方-lg25-2lg2
=16+4-8-2
=10